A block of mass 500 g is connected to a spring of spring constant k = 312.5N / m on a frictionless table. The spring is held firmly at the other end. The block is pulled a distance of 5 cm and then released to make SHM. Calculate the time period of its oscillations - VgyanHub

Question:

A block of mass 500 g is connected to a spring of spring constant k = 312.5N / m on a frictionless table. The spring is held firmly at the other end. The block is pulled a distance of 5 cm and then released to make SHM. Calculate the time period of its oscillations

Options :

(a) 2.0s
(b) 1.75s
(c) 0.5s
(d) 0.25s

Answer :

(d) 0.25s

Answer Steps :

step 1

step 2

Video Tutorial

Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

Explore Our Courses