The magnetic field in a certain region of space is given by B=8.35×10^−2i T. A proton is shot into the field with velocity v=(2×10^5i + 4×10^5j)m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz-plane will be ( mass of proton=1.67×10^−27kg) - VgyanHub

Question:

The magnetic field in a certain region of space is given by B=8.35×10⁻²i T. A proton is shot into the field with velocity v=(2×10⁵i + 4×10^⁵j)m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz-plane will be ( mass of proton=1.67×10⁻²⁷kg)

Options :

(a) 0.053 m
(b) 0.136m
(c) 0.157 m
(d) 0.236m

Answer :

(c) 0.157 m

Answer Steps :

step 1:

step 2:

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