A particle is executing SHM along a straight line. Its velocities at distances x₁ and x2 from the mean position are V₁ and V₂ respectively. Its time period is

Question:

A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is

Options :

(a) 2π√x2^2-x1^2/V1^2-V2^2
(b) 2π√V1^2+V2^2/x1^2+x2^2
(c) 2π√V1^2-V2^2/x1^2-x2^2
(d) 2π√x1^2+x2^2/V1^2-V2^2

Answer :

(a) 2π√x₂²-x₁²/V₁²-V₂²

Answer Steps :

step 1

step 2

Video Tutorial

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

Online Support

Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

Explore Our Courses

Access To All Courses from VgyanHub

Popular Courses

Company

Need Some Help?