A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in second is

Question:

Options :

(a) 1/2π√3
(b) 2π√3
(c) 2π/√3
(d) √3/2π

Answer :

Answer Steps :

step 1

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Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

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