Question:

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by 60° is W. Now the torque required to keep the magnet in this new position is

Options :

  • (a) √3W /2
  • (b) 2W / √3
  • (c) W / √3
  • (d) √3W

Answer :

(d) √3W

Answer Steps :

step 1:

step 2:

Video Tutorial