A capacitor 50 µF is connected to a.c. source e = 220sin 50 t (e in volt, t in second). The value of peak current is: - VgyanHub

Question:

A capacitor 50 µF is connected to a.c. source e = 220sin 50 t (e in volt, t in second). The value of peak current is:

Options :

(a) 0.55 A
(b) √2 A
(c) 0.55/√2 A
(d) √2/0.55 A

Answer :

(a) 0.55 A

Answer Steps :

step 1

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