A conducting square frame of side 'a' and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to - VgyanHub

Question:

A conducting square frame of side ‘a’ and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity ‘V’. The emf induced in the frame will be proportional to

Options :

(a) 1/(2x-a)2
(b) 1/(2x+a)2
(c) 1/(2x - a)(2x+a)
(d) 1/x2

Answer :

(c) 1/(2x – a)(2x+a)

Answer Steps :

Step 2:

Step 3:

Step 4:

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