A disc of Mars 50KG and radius 1m is rotating at 180 rpm. The torque required to rotate the disc in opposite direction with the same speed in 24 seconds is

Question:

24.A disc of Mars 50KG and radius 1m is rotating at 180 rpm. The torque required to rotate the disc in opposite direction with the same speed in 24 seconds is

Options :

a) (20.5)πNm
b) (16.5)πNm
c) (8.5)πNm
d) (12.5)πNm

Answer :

d) (12.5)πNm

Answer Steps :

Step1 :-

Step2 :-

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Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

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