A particle starts oscillating simple harmonically from its equilibrium position. Then the ratio of kinetic and potential energy of the particle at time T / 12 is ( T - time period)

Question:

A particle starts oscillating simple harmonically from its equilibrium position. Then the ratio of kinetic and potential energy of the particle at time T / 12 is ( T – time period)

Options :

(a) 2:1
(b) 1:2
(c) 1:3
(d) 3:1

Answer :

Answer Steps :

step 1

step 2

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Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

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