A proton accelerated by a potential difference V = 500 kV flies through a uniform transverse magnetic field with induction B = 0.51 T. The field occupies a region of space d =10 cm in thickness. Find the angle a through which the proton deviates from the initial direction of its motion. - VgyanHub

Question:

A proton accelerated by a potential difference V = 500 kV flies through a uniform transverse magnetic field with induction B = 0.51 T. The field occupies a region of space d =10 cm in thickness. Find the angle a through which the proton deviates from the initial direction of its motion.

Options :

(a)15^0
(b)30^0
(c)45^0
(d)60^0

Answer :

(b)30⁰

Answer Steps :

step 1:

step 2:

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