A rectangular loop has a sliding connector PQ of length l and resistance RΩ and it is moving with a speed u as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents I1,I2 and l are

Question:

Options :

(a) I1 =I2 = BLv/6R , I=BLv/3R
(b) I1 =-I2 = BLv/R , I= 2BLv/R
(c) I1 =I2 = BLv/3R , I= 2BLv/3R
(d) I1 =I2 = I= BLv/R

Answer :

Answer Steps :

Four particles each of mass m are placed at the corners of a square of side length l. The radius of gyration of the system about an axis perpendicular to the square and passing through its centre is [EAMCET (Med.) 2000]

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Four particles each of mass m are placed at the corners of a square of side length l. The radius of gyration of the system about an axis perpendicular to the square and passing through its centre is [EAMCET (Med.) 2000]

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