A rod lies along the x-axis with one end at the origin and the other at x→∞. It carries a uniform charge λC/m. The electric field at the point x = -a on the axis will be

Question:

Options :

a) Ē = λ/(4πε₀α)(-î)
b) Ē = λ/(4πε₀α)(î)
c) Ē = λ/(2πε₀α)(-î)
d) Ē = λ/(2πε₀α)(î)

Answer :

a) Ē = λ/(4πε₀α)(-î)

Answer Steps :

Solution :-

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