A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8rad−s −2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g=10 ms −2 ) - VgyanHub

Question:

3.A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8rad−s −2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g=10 ms −2 )

Options :

a) 2kgm^2
b) 1kgm^2
c) 4kgm^2
d) 8kgm^2

Answer :

a) 2kgm^2

Answer Steps :

Solution :-

Video Tutorial

Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

Explore Our Courses