Alternating emf of e = 220 sin 100 лt is applied to a circuit containing an inductance of (1/π) henry. Write an equation for instantaneous current through the circuit. What will be the reading of the AC galvanometer connected in the circuit?

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An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

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An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

In an a. c. circuit the instantaneous current and e.m.f. are represented as: I = I0 sin(ωt – π/6) and E = E0 sin(ωt + π /3) respectively. The voltage leads the current by

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