An electron moving with the speed 5×10⁶m per sec is shouted parallel to the electric field of intensity 1×10³ N/C . Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of e = 9×10⁻³1Kg. charge = 1.6×10⁻¹⁹C) - VgyanHub

Question:

An electron moving with the speed 5×10⁶m per sec is shouted parallel to the electric field of intensity 1×10³ N/C . Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of e = 9×10⁻³1Kg. charge = 1.6×10⁻¹⁹C)

Options :

a) 7 m
b) 0.7 mm
c) 7 cm
d) 0.7 cm

Answer :

c) 7 cm

Answer Steps :

Solution :-

Step1 :-

Step2 :-

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