An inductance of 300/π mH, a capacitance of 1/π mF and a resistance of 20 Ω are connected in series with a.c. source of 240 V, 50 Hz. The phase angle by which the voltage leads the current in the circuit is

Question:

Options :

(a) tan^-1(1)
(b) tan^-1(1/√3)
(c) tan^-1(0)
(d) (√3)

Answer :

(a) tan^-1(1)

Answer Steps :

step 1

step 2

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An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

In an a. c. circuit the instantaneous current and e.m.f. are represented as: I = I0 sin(ωt – π/6) and E = E0 sin(ωt + π /3) respectively. The voltage leads the current by

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