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qUESTIONS

11th-jee

Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is

11th-jee

The position vector of a particle is determined by the expression r̄ = 3t²î+4r²ĵ+7k̂ The distance traversed in first 10 sec is

11th-jee

An object of m kg with speed of v m/s strikes a wall at an angle and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be

11th-jee

The position vector of a particle is r=a[cosωtî+sinωtĵ]. The velocity of the particle is

11th-jee

There are two force vectors, one of 5 N and other of 12 N at what angle the two vectors be added to get resultant vector of 17 N, 7 N and 13 N respectively

11th-jee

The angle between the two vectors Ā = 3î + 4ĵ + 5k̂ and B̅ = 3î + 4ĵ – 5k̂ will be

11th-jee

The unit vector parallel to the resultant of the vectors Ā = 4î + 3ĵ + 6k̂ and B̅ = -î + 3ĵ – 8k̂ is

11th-jee

A truck travelling due north at 20 m/s turns west and travels at the same speed. The change in its velocity be

11th-jee

The angle made by the vector A = î + ĵ with x- axis is

11th-jee

A vector is represented by 3î + ĵ + 2k̂. Its length in XY plane is

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