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qUESTIONS

12th-jee

Find the equivalent resistance across the terminals of source of e.m.f. 24 V for the circuit shown in figure on

12th-jee

The equivalent resistance between the points P and Q in the network given here is equal to (given r=3/2Ω )

12th-jee

What is the equivalent resistance between the points A and B of the network

12th-jee

An infinite sequence of resistances is shown in the figure. The resultant resistance between A and B will be, when R1 =1ohm and R2 = 2ohm

12th-jee

Three resistances of 4Ω each are connected as shown in figure. If the point D divides the resistance into two equal halves, the resistance between point A and D will be

12th-jee

Two wires of the same material and equal length are joined in parallel combination. If one of them has half the thickness of the other and the thinner wire has a resistance of 8 ohms, the resistance of the combination is equal to

12th-jee

Four resistances 10Ω , 5Ω , 7Ω  and 3Ω  are connected so that they form the sides of a rectangle AB, BC, CD and DA respectively. Another resistance of 10Ω  is connected across the diagonal AC. The equivalent resistance between A and B is

12th-jee

A copper wire of resistance R is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance

12th-jee

Three resistances each of 1 ohm, are joined in parallel. Three such combinations are put in series, then the resultant resistance will be

12th-jee

The equivalent resistance of the arrangement of resistances shown in adjoining figure between the points A and B is

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