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qUESTIONS

MCQs-PYQs-12th-jee

Which of the following will represent Coulomb’s Law?

MCQs-PYQs-12th-jee

A charge q is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is

MCQs-PYQs-12th-jee

In a region, the intensity of an electric field is given by E=2i+3j+k in NC⁻¹. The electric flux through a surface A S = 10i m² in the region is

MCQs-PYQs-12th-jee

The inward and outward electric flux for a closed surface in units of N-m²/C are respectively 8×10³ and 4×10³.Then the total charge inside the surface is

MCQs-PYQs-12th-jee

The S.I. unit of electric flux is

MCQs-PYQs-12th-jee

Two electric dipoles of moment p and 64 p are placed in opposite direction on a line at a distance of 25 cm. The electric field will be zero at point between the dipoles whose distance from the dipole of moment p is

MCQs-PYQs-12th-jee

The distance between H+ and Cl ions in HCl- molecule is 1.28 Å. What will be the potential due to this dipole at a distance of 12 Å on the axis of dipole

MCQs-PYQs-12th-jee

An electric dipole coincides on the z-axis and its centre coincides with the origin of the cartesian coordinate system. The electric field at an axial point at a distance z from the origin isEᶻ and the electric field at an equatorial point at a distance y from the origin is Eʸ. Given thaty=z))a, the value of | Eᶻ/Eʸ | is

MCQs-PYQs-12th-jee

The electric field due to an electric dipole at a distance r from its centre in axial position is E. If the dipole is rotated through an angle of 90° about its perpendicular axis, the electric field at the same point will be

MCQs-PYQs-12th-jee

The ratio of electric field and potential (E/V) at midpoint of electric dipole, for which separation is I

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