Skip to content
  • +91 87932 47779
  • Email Us
Phone
Online Support

+91 87932 47779

Logo
Email
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
Menu
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
vgyanhub logo
Free Tests
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Try Out Our Free Tests

qUESTIONS

Textbook Solutions-11th-MH

An artificial satellite revolves around a planet in circular orbit close to its surface. Obtain the formula for period of the satellite in terms of density p and radius R of planet.

Textbook Solutions-11th-MH

Calculate the period of revolution of a polar satellite orbiting close to the surface of the Earth. Given R = 6400 km, g = 9.8 m/s2.

Textbook Solutions-11th-MH

Show that the critical velocity of a body revolving in a circular orbit very close to the surface of a planet of radius R and mean density p is 2R

Textbook Solutions-11th-MH

What will be the change in potential energy of a body of mass m when it is raised from height R, above the Earth’s surface to 5/2 R, above the Earth’s surface? R and M, are the radius and mass of the Earth respectively.

Textbook Solutions-11th-MH

Find the gravitational force between the Sun and the Earth. Given Mass of the Sun = 1.99×10^30 kg Mass of the Earth = 5.98×10^24 kg. The average distance between the Earth and the Sun is 1.5×10^11 m.

Textbook Solutions-11th-MH

At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface, given radius of Earth is 6400 km.

Textbook Solutions-11th-MH

At what distance above the surface of Earth the acceleration due to gravity decreases by 10% of its value at the surface? (Radius of Earth = 6400 km)

Textbook Solutions-11th-MH

Find the acceleration due to gravity on a planet that is 10 times as massive as the Earth and with radius 20 times of the radius of the Earth (g = 9.8 m/s2).

Textbook Solutions-11th-MH

Calculate the acceleration due to gravity on the surface of moon if mass of the moon is 1/80 times that of the Earth and diameter of the moon is 1/4 times that of the Earth (g = 9.8 m/s2)

Textbook Solutions-11th-MH

Calculate mass of the Earth from given data, Acceleration due to gravity g = 9.81 m/s2, Radius of the Earth RE = 6.37 × 106 m, G = 6.67 × 10-11 N m2/kg2

1 2 3
vgyanlogo
Access To All Courses from VgyanHub

Popular Courses

  • 12th Physics | Maharashtra State Board | Full Course
  • Physics | JEE Main | Full Course
  • Physics | NEET | Full Course

Company

  • Home
  • About Us
  • Courses
  • Testimonials
  • Knowledge Base

Need Some Help?

  • Contact Us

© Copyright 2024 VgyanHub & Designed by PanGrow Tech Pvt. Ltd.