Skip to content

+91 87932 47779

Email Us

Online Support

+91 87932 47779

Email Us At
- vgyanhubpune@gmail.com
- vgyanhubdhule@gmail.com

Menu

Email Us At
- vgyanhubpune@gmail.com
- vgyanhubdhule@gmail.com

Menu

Home
About Us
Courses
Knowledge Base
Events
Testimonials
Contact Us

Home
About Us
Courses
Knowledge Base
Events
Testimonials
Contact Us

Menu

Home
About Us
Courses
Knowledge Base
Events
Testimonials
Contact Us

Try Out Our Free Tests

qUESTIONS

The difference between the two molar specific heats of a gas is 8000 J k * g⁻¹ * K⁻¹ . If the ratio of the two specific heats is 1.65, calculate the two molar specific heats.

Given the values of the two principal specific heats, Sp = 3400 cal kg⁻¹ * K⁻¹ and Sv = 2400 cal kg⁻¹ * K⁻¹ for the hydrogen gas, find the value of J if the universal gas constant R = 8300J kg⁻¹ * K⁻¹ .

At 300 K, what is the rms speed of Helium atom? [mass of He atom is 4u, 1u = 1.66 * 10² – 27 * kg kB = 1.38 * 10² – 23 * J / K ]

Obtain the mean free path of nitrogen molecule at 0 °C and 1.0 atm pressure. The molecular diameter of nitrogen is 324 pm (assume that the gas is ideal).

1 2 3

vgyanlogo

Access To All Courses from VgyanHub

Popular Courses

12th Physics | Maharashtra State Board | Full Course
Physics | JEE Main | Full Course
Physics | NEET | Full Course

Company

Home
About Us
Courses
Testimonials
Knowledge Base

Need Some Help?

Contact Us

© Copyright 2024 VgyanHub & Designed by PanGrow Tech Pvt. Ltd.