Skip to content
  • +91 87932 47779
  • Email Us
Phone
Online Support

+91 87932 47779

Logo
Email
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
Menu
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
vgyanhub logo
Free Tests
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Try Out Our Free Tests

qUESTIONS

11th-mht

A projectile thrown from the ground has an initial speed u and its direction makes an angle θ with the horizontal. If at maximum height from the ground, the speed of the projectile is half its initial speed of projection, then the maximum height reached by the projectile is

11th-mht

Two balls A and B are projected at angles 45° and 60° and the maximum heights reached are same, what is the ratio of their initial velocities?

11th-mht

An aeroplane is flying in a horizontal direction with a velocity of 540 km/hr at a height of 1960 m. When it is vertically above the point A on the ground, a body is dropped from it. The body strikes the ground at point B. The distance AB is equal to:

11th-mht

A bird flies for 4 s with a velocity of |t−2| m/s^-1 in a straight line, Where t= time in seconds. It covers a distance of

11th-mht

The displacement time graph for two particles A and B are straight lines inclined at angles of 30 degree and 60 degree with the time axis. The ratio of velocities of VA:VB

11th-mht

The equation of the trajectory of a ball projected at an angle ‘ θ ‘ with the horizontal, is given is y= √3x − gx^2/2. The initial velocity of the ball is :

11th-mht

A body of mass (m) moving along a straight line covers half the distance with a speed of 2 m/s^-1. The remaining half of the distance is covered in two equal time intervals with a speed of 6 m/s^-1 and 5 m/s^−1 respectively. The average speed of the particle for the entire journey is.

11th-mht

The numerical ratio of average velocity to average speed is equal to

11th-mht

An airplane flies 400 m north and 300 m south and then flies 1200 m upwards then net displacement is:

11th-mht

A body moves 6m north, 8m east, and 10m vertically upwards, what is its resultant displacement from the initial position

1 2 3 4
vgyanlogo
Access To All Courses from VgyanHub

Popular Courses

  • 12th Physics | Maharashtra State Board | Full Course
  • Physics | JEE Main | Full Course
  • Physics | NEET | Full Course

Company

  • Home
  • About Us
  • Courses
  • Testimonials
  • Knowledge Base

Need Some Help?

  • Contact Us

© Copyright 2024 VgyanHub & Designed by PanGrow Tech Pvt. Ltd.