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qUESTIONS

The mass and radius of the earth and moon are M1, R1 and M2, R2 respectively. Their centres are at a distance ‘d’ apart. The minimum speed with which a body of mass ‘m’ should be projected from a distance 2d/3 from the centre of M1, so as to escape to ∞ is:

The depth below the earth’s surface at which the acceleration due to gravity ‘g’ becomes ‘g/n’

If ‘M’ and ‘R’ are mass and radius of earth respectively and ‘m’ is mass of a satellite revolving in the circular orbit of radius ‘r’ at height ‘h’ from the surface of earth. (G= Gravitational constant) Match column I with column II.

A body weight ‘W’ newton on the surface of the earth. Its weight at a height equal to half the radius of the earth, will be:

A satellite of mass ‘m’ revolving around the earth of radius ‘r’ has kinetic energy ‘E’. Its angular momentum is:

If the radius of a planet is ‘R’ and density is ‘p’, the escape velocity ‘v’ of any body from its surface will be:

A launching vehicle carrying an artificial satellite of mass ‘m’ is set for launch, on the earth’s surface. If the satellite is intended to move in a circular orbit of radius ‘7R’, the minimum energy required to be spent by the launching vehicle is: (G= Universal gravitation constant, M and R be the mass and radius of the earth)

Earth revolves round the sun in a circular orbit of radius ‘R’. The angular momentum of the moving earth is directly proportional to:

The height above the earth’s surface at which the acceleration due to gravity becomes (1/n) times the value at the surface is (R = radius of the earth)

If ‘T is the length of a day of earth, ‘M’ and ‘R’ are the mass and radius of the earth respectively, then the height of a geostationary satellite is: [G= Universal gravitational constant]

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