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qUESTIONS

The time period of a simple pendulum on a freely moving artificial satellite is

The angular velocity of the earth with which it has to rotate so that acceleration due to gravity on 60° latitude becomes zero is (Radius of earth = 6400 km At the poles g = 10 km-²)

Assuming earth to be a sphere of radius R, if g30 degree. is value of acceleration due to gravity at latitude of 30° and g at the equator, the value of g – g30 degree is

If the earth stops rotating, the value of g at the equator

For a body lying on the equator to appear weightless, what should be the angular speed of the earth? (Take g = radius of earth = 6400 km)

Acceleration due to gravity is maximum at (R is the radius of earth)

Spot the wrong statement: The acceleration due to gravity ‘g’ decreases if

The weight of an object in the coal mine, sea level, at the top of the mountain are W₁, W₂ and W3, respectively, then

The acceleration due to gravity is g at a point having distant from the centre of earth of radius R. If r< R, then

Radius of earth is around 6000 km. The weight of body at height of 6000 km from earth surface becomes

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