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qUESTIONS

Nuclear radii may be measured by scattering high energy electrons from nuclei. What is the de-Broglie wavelength for 200 MeV electrons?

According to De-Broglie hypothesis if there is an electron of mass ‘m’ and is accelerated by potential difference ‘V’, then its associated wavelength is ‘λ’. When a proton of mass ‘M’ is accelerated through potential difference ‘9V’ then the wavelength associated with it is: [MHT-CET 2021]

According to Einstein’s photoelectric equation, the correct graph between the kinetic energy (K.E.) of photoelectrons emitted and the frequency (v) of incident radiation is: [MHT-CET 2021]

Photoelectric emission takes place from a certain metal at threshold frequency ‘v’. If the radiation of frequency ‘2v’ is incident on the metal plate, the maximum velocity of the emitted photoelectron will be: (m = mass of electron, h = Planck’s constant) [MHT-CET 2021]

If the de-Broglie wavelength of the electron in the ground state is ‘λ,’ and that in the n = 4 level is ‘2’, then: [MHT-CET 2022]

The work functions for metals A, B and C are 1.92 eV, 2.0 eV and 5 eV respectively. The metal(s) which will emit photoelectrons for incident radiation of wavelength 4100 Å is/are:

Energy of photon whose frequency is 10^12 MHz is: [MHT-CET 2022]

The energy that should be added to an electron to reduce its de-Broglie wavelength from 10^-10 m to 0.5 x 10^-10 m will be: [MHT-CET 2022]

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