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qUESTIONS

The work done in splitting a waterdrop of radius ‘R’ into 64 droplets is ( T = surface tension of water)

The soap bubble in air has surface tension 0.027 Nm-¹. The excess pressure inside a bubble of diameter 30 mm in SI unit is:

A capillary tube of radius ‘r’ is immersed in water and water rises to height “h”. The mass of water in the capillary tube is ‘M’. Another capillary of radius ‘2r’ is immersed in water. The mass of water that will rise in this tube is ‘M1’. The ratio M/M1 is:

Two small drops of mercury coalesce to form a single large drop. The ratio of total surface energy before and after the change is:

According to newton’s law of viscosity, for a stream line flow, viscous force (F) between any two layer is:(A = area of layer)

The excess pressure inside a soap bubble of volume ‘V1’ is twice the excess pressure inside a second soap bubble of volume ‘ V2’ The value of V1/V2 is:

When liquid flows through a tube, the Reynold’s number is 1500. the flow of liquid is:

A soap bubble of radius 1/√π cm is expanded to have double the radius. If surface tension of soap solution is 30 dyne/ cm, then the work done is:

The upward force due to surface tension (7) in a capillary tube is balancing downward weight of 75 ×10-⁴ N The inner circumference of the tube is:

The liquid meniscus in a capillary tube will be convex if the angle of contact is:

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