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A particle starts oscillating simple harmonically from its equilibrium position. Then the ratio of kinetic and potential energy of the particle at time T / 12 is ( T – time period)

The time taken by a particle executing simple harmonic motion of period ‘T’ to move from the mean position to half the maximum displacement is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

The length of the seconds pendulum is 1 m on earth. If the mass and diameter of any planet is 1.5 times that of the earth, the length of the seconds pendulum on that planet will be nearly

Two simple harmonic motions of angular frequency 100 rad/sec and 1000 rad/s have the same displacement amplitude. The ratio of their maximum acceleration is

If a body is executing simple harmonic motion then

A body executing simple harmonic motion has a maximum acceleration equal to 24 ms¯² and maximum velocity of 16 ms-¹, the amplitude of the simple harmonic motion is

The mass M shown in the figure oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is

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