Example 10.3 Consider a square loop of wire loaded with a glass bulb of mass m hanging vertically, suspended in air with its one part in a uniform magnetic field B with its direction coming out of the plane of the paper . Due to the current I flowing through the loop, there is a magnetic force in upward direction. Calculate the current I in the loop for which the magnetic force would be exactly balanced by the force on mass m due to gravity.

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The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

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The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

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