Force between two identical charges placed at a of in vacuum is F. Now a dielectric slab of dielectric constant 4 is inserted between these two charges, then the force between the charges will become

Question:

Options :

(a) F
(b) 3/5 F
(c) 4/9 F
(d) F/4

Answer :

(d) F/4

Answer Steps :

step 1

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