Question:

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take g = 10m/s²)

Options :

  • (a) 5:7
  • (b) 7:5
  • (c) 3:6
  • (d) 6:3

Answer :

(b) 7:5

Answer Steps :

Step 1:

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