Question:

If ‘T is the length of a day of earth, ‘M’ and ‘R’ are the mass and radius of the earth respectively, then the height of a geostationary satellite is: [G= Universal gravitational constant]

Options :

  • (a) [GMT^2/4π^2]^1/3 -R
  • (b) [4π^2 GM/R^2]^1/3 -R
  • (c) [GMT^2/4π^2]^1/3 +R
  • (d) [4π^2 GM/T^2]^1/3

Answer :

(a) [GMT2/4π2]1/3 -R

Answer Steps :

step 1

step 2

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