In a Wheatstone's bridge, three resistance P, Q and R are connected in the three arms and the fourth arm is formed by two resistances S₁ and S2 connected in parallel. The condition for the bridge to be balanced will be [2006]

Question:

In a Wheatstone’s bridge, three resistance P, Q and R are connected in the three arms and the fourth arm is formed by two resistances S₁ and S2 connected in parallel. The condition for the bridge to be balanced will be [2006]

Options :

a)P/Q= R(S1+S2)/S1S2
b)P/Q= R(S1+S2)/2S1S2
c)P/Q= R/S1+S2
d)P/Q= 2R/S1+S2

Answer :

a)P/Q= R(S1+S2)/S1S2

Answer Steps :

Step:-1

Video Tutorial

An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

A 1 µF condenser is charged to 50 V. The charging battery is then disconnected and a 10 mH coil is connected across the capacitor so that LC oscillations occur. What is the maximum current in the coil ? Assume that the circuit contains no resistance. The capacity of a pure capacitor is 1 F. In d.c. circuits, its effective resistance will be

In an a. c. circuit the instantaneous current and e.m.f. are represented as: I = I0 sin(ωt – π/6) and E = E0 sin(ωt + π /3) respectively. The voltage leads the current by

Online Support

Related Questions

An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

In an a. c. circuit the instantaneous current and e.m.f. are represented as: I = I0 sin(ωt – π/6) and E = E0 sin(ωt + π /3) respectively. The voltage leads the current by

Explore Our Courses

Access To All Courses from VgyanHub

Popular Courses

Company

Need Some Help?