Question:

In single slit diffraction experiment, first minimum observed for wavelength ‘λ1‘ coincides with first maximum obtained using wavelength ‘λ2‘. If λ1= 6300 Å, then λ2 is

Options :

  • (a) 5400 Å
  • (b) 6300 Å
  • (c) 3150 Å
  • (d) 4200 Å

Answer :

(d) 4200 Å

Answer Steps :

step 1

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