Periodic time of a satellite revolving above Earth's surface at a height equal to radius of Earth is [g is acceleration due to gravity at Earth's surface] - VgyanHub

Question:

Periodic time of a satellite revolving above Earth’s surface at a height equal to radius of Earth is [g is acceleration due to gravity at Earth’s surface]

Options :

(a) 2π√2R/g
(b) 4√2π√R/g
(c) π√R/g
(d) 8π√R/g

Answer :

(b) 4√2π√R/g

Answer Steps :

step 1

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