Question:

6.Point masses m1and m2 are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω0 is minimum, is given by :

Options :

  • a) x = (m1/m2)L
  • b) x = (m2/m1)L
  • c) x = m2L/(m1 + m2)
  • d) x = m1L/(m1 + m2)

Answer :

c) x = m2L/(m1 + m2)

Answer Steps :

Method1 :-

Step1 :-

Step2 :-

Method2 :-

 

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