The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B₁. When the dipole moment is double by keeping the current constant, the magnetic field at the centre of loop is B2. The ratio B1/B2 is - VgyanHub

Question:

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B₁. When the dipole moment is double by keeping the current constant, the magnetic field at the centre of loop is B2. The ratio B1/B2 is

Screenshot 2025-01-05 151957

Options :

(a)√2
(b) 1/√2
(c) 2
(d)√3

Answer :

Ans :- (a)√2

Answer Steps :

Step 1:-

Video Tutorial

Related Questions

An alternating voltage source is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is:

A 1 µF condenser is charged to 50 V. The charging battery is then disconnected and a 10 mH coil is connected across the capacitor so that LC oscillations occur. What is the maximum current in the coil ? Assume that the circuit contains no resistance. The capacity of a pure capacitor is 1 F. In d.c. circuits, its effective resistance will be

In an a. c. circuit the instantaneous current and e.m.f. are represented as: I = I0 sin(ωt – π/6) and E = E0 sin(ωt + π /3) respectively. The voltage leads the current by

Explore Our Courses