Skip to content
  • +91 87932 47779
  • Email Us
Phone
Online Support

+91 87932 47779

Logo
Email
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
Menu
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
vgyanhub logo
Free Tests
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Try Out Our Free Tests

Question:

4.The work done in increasing the size of a soap film from 10 cmx 6 cm to 10 cm x 11 cm is 3 x10^4 joule. The surface tension of the film is

Options :

  • a) 1.5x10^-2 N/m
  • b) 3.0x10^-2 N/m
  • c) 6.0x10^-2 N/m
  • d) 11.0x10^-2 N/m

Answer :

b) 3.0×10^-2 N/m

Answer Steps :

Video Tutorial

Related Questions

Moment of inertia of a thin uniform disc

Read More »

Moment of inertia of a thin uniform ring

Read More »

Rotational Kinetic Energy

Read More »
« Previous Next »
Explore Our Courses
  • MHT-CET Mock Test (PCMB) | Pack of 10 Tests
  • NEET Mock Test (PCB) | Pack of 10 Test​
  • JEE Mock Test (PCM) | Pack of 10 Test
  • Physics | NEET | Full Course
  • 11th Physics | Maharashtra Board | Full Course
  • Physics | JEE Main | Full Course
  • Physics | 12th + MHT-CET | Maharashtra Board
  • 12th Physics | Maharashtra State Board | Full Course
  • 12th Maharashtra State Board | Prepare Physics in 3 Days
  • MHT-CET Physics Crash Course Marathon Batch 2023-24
  • JEE Main Crash Course Brahmastra Batch
  • Physics NEET Crash Course 2023-24
vgyanlogo
Access To All Courses from VgyanHub

Popular Courses

  • 12th Physics | Maharashtra State Board | Full Course
  • Physics | JEE Main | Full Course
  • Physics | NEET | Full Course

Company

  • Home
  • About Us
  • Courses
  • Testimonials
  • Knowledge Base

Need Some Help?

  • Contact Us

© Copyright 2024 VgyanHub & Designed by PanGrow Tech Pvt. Ltd.