Question:

Two boys are standing at the ends A and B of a ground where AB = a The boy at B starts running in a direction perpendicular to AB with velocity o1 The boy at A starts running simultaneously with velocity u and catches the other boy in a time t, where t is

Options :

  • (a) a/√v²+v1²
  • (b) √a²/v²-v1²
  • (c) a / (v-v1)
  • (d)a/(v+v1)

Answer :

(b) √a²/v²-v1²

Answer Steps :

Step 1:

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