Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is - VgyanHub

Question:

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v₁. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is

Options :

(a) a/√v^2 + v1^2
(b) √a^2/v^2 - v1^2
(c) a/(v - v1)
(d) a/(v + v1)

Answer :

(b) √a²/v² – v1²

Answer Steps :

step 1

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