Two simple harmonic motions are represented by the equations y1 = 0.1sin(100πt + π/3) and y2 = 0.1cos πt The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

Question:

Two simple harmonic motions are represented by the equations y₁ = 0.1sin(100πt + π/3) and y₂ = 0.1cos πt The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

Options :

(a) -π/3
(b) π/6
(c) -π/6
(d) π/3

Answer :

Answer Steps :

step 1

step 2

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Related Questions

The kinetic energy of a particle executing a linear SHM is 16 J, when it is in the mean position. If the amplitude is 25 cm, periodic time of the particle in second is (Mass of the particle = 51.2 g)

A body of mass ‘M’ executes SHM Along x-axis with frequency ‘n’. At a distance x from the mean position, the body has kinetic energy ‘K’ and potential energy ‘P’. The amplitude of oscillation of the SHM is

The bob of a simple pendulum of ‘length ‘l’ is pulled through an angle ‘θ’ from its equilibrium position and them released. When it passes through its equilibrium position, its speed is given by: (g = acceleration due to gravity)

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