What is the maximum acceleration of the particle doing the SHM? y=2sin[πt2+ϕ], where 2 is in cm. - VgyanHub

Question:

What is the maximum acceleration of the particle doing the SHM? y=2sin[πt2+ϕ], where 2 is in cm.

Options :

(a) π/2 cm/s^2
(b) π^2/2 cm/s^2
(c) π/4 cm/s^2
(d) π^2/4 cm/s^2

Answer :

(b) π²/2 cm/s²

Answer Steps :

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