Skip to content
  • +91 87932 47779
  • Email Us
Phone
Online Support

+91 87932 47779

Logo
Email
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
Menu
  • Email Us At
    • vgyanhubpune@gmail.com
    • vgyanhubdhule@gmail.com
vgyanhub logo
Free Tests
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Menu
  • Home
  • About Us
  • Courses
  • Knowledge Base
  • Events
  • Testimonials
  • Contact Us
Try Out Our Free Tests

qUESTIONS

11th-jee

A block of mass ‘m’ is connected to another block of mass ‘M’ by a spring (massless) of spring constant ‘k’. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force ‘F’ starts acting on the block of mass ‘M’ to pull it. Find the force on the block of mass ‘m’

11th-jee

Two blocks A and B of masses 2m and m, respectively, are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in the figure. The magnitudes of acceleration of A and B, immediately after the string is cut, are respectively

11th-jee

The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle should be

11th-jee

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

11th-jee

A mass of 10kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10ms 2)

11th-jee

A particle of mass m is moving is a straight line with momentum p. Starting at time t = 0, a force F=kt acts in the same direction on the moving particle during time interval T so that its momentum changes from p to 3p. Here k is a constant. The value of T is

11th-jee

If 10^22 gas molecules each of mass 10^-26 kg collide with a surface (perpendicular to it) elastically per second over an area 1m2 with a speed 10^4 m/s, the pressure exerted by the gas molecules will be of the order of

11th-jee

A man (mass 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms1 with respect to the man. The speed of the man with respect to the surface is

11th-jee

The amount of heat energy, required to raise the temperature of 1 g of Helium at NTP from T1K to T2K is

11th-jee

The ratio of the specific heats Cp/Cv = γ in terms of degrees of freedom (f) is given by

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68
vgyanlogo
Access To All Courses from VgyanHub

Popular Courses

  • 12th Physics | Maharashtra State Board | Full Course
  • Physics | JEE Main | Full Course
  • Physics | NEET | Full Course

Company

  • Home
  • About Us
  • Courses
  • Testimonials
  • Knowledge Base

Need Some Help?

  • Contact Us

© Copyright 2024 VgyanHub & Designed by PanGrow Tech Pvt. Ltd.