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qUESTIONS

What is the maximum acceleration of the particle doing the SHM? y=2sin[πt2+ϕ], where 2 is in cm.

Two simple harmonic motions of angular frequency 100 and 1000 rad s¹ have the same displacement amplitude. The ratio of their maximum accelerations is

The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

Which one of the following equations of motion represents simple harmonic motion?

The angular velocities of three bodies in simple harmonic motion are w1, w2, w3 with their respective amplitudes as A1, A2, A3,. If all the three bodies have same mass and velocity, then

A body is executing simple harmonic motion with an angular frequency 2 rad/s. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm, is

A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and time period T. The speed of the pendulum at X = A/2 will be

The displacement of a particle is represented by the equation y = 3cos(π/4 – 2wt) The motion of the particle is

The displacement of a particle along the x-axis is given by x = a sinwt. The motion of the particle corresponds to

Out of the following functions representing motion of a particle which represents SHM

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