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qUESTIONS

If the density of a small planet is the same as that of earth, while the radius of the planet is 0.2 times that of the earth, the gravitational acceleration on the surface of that planet is

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be

If the mass of the Sun were ten times smaller and the universal gravitational constant were ten time larger in magnitude, which of the following is not correct

Starting from the centre of the earth having radius R, the variation of g (acceleration due to gravity) is shown by

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth. Then

A particle of mass M is situated at the centre of a spherical shell of same mass and radius a. The magnitude of the gravitational potential at a point situated at a/2 distance from the centre, will be

Infinite number of masses, each 1 kg, are placed along the x- axis at x=±1m, ± 2m, ± 4m, ±8m,±16m…………. The magnitude of the resultant gravitational potential in terms of gravitational constant G at the origin (x = 0) is

At what height from the surface of earth the gravitation potential and the value of g are -5.4×10^7Jkg^-2 and 6.0ms^-2 respectively? Take the radius of earth as 6400 km

A body of mass ‘m’ is taken from the earth’s surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be

A particle of mass m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is

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