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Two simple harmonic motions are represented by the equations y1 = 0.1sin(100πt + π/3) and y2 = 0.1cos πt The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at distance 2A/3 from equilibrium position. The new amplitude of the motion is

A mass m attached to a spring oscillates every 2 s. If the mass is increased by 2 kg, then time-period increases by 1 s. The initial mass is

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of increased length is

A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is

A coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency w. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is ẞ. Then its time period of vibration will be

A particle is executing SHM along a straight line. Its velocities at distances x₁ and x2 from the mean position are V₁ and V₂ respectively. Its time period is

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