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qUESTIONS

A string of length 2m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500Hz, then the waves would travel on it with a velocity of

The equation of a stationary wave along a stretched string is given by y = 4 sin 2πx/3 cos 40πt where x and y are in cm and t is in sec. The separation between two adjacent nodes is

The superposing waves are represented by the following equations: y1=5 sin 2π(10t−0.1x), y2=10 sin2π(20t−0.2x). Ratio of intensities Imax / Imin will be

The phase difference between the two particles situated on both the sides of a node is

Two travelling waves y1=A sin [k(x-ct)] and y2=A sin [k(x+ct)] are superimposed on string. The distance between adjacent nodes is

Sound wave of frequency v=600Hz fall normally on a perfect reflecting wall. The shortest distance from the wall at which particles of the medium will have maximum displacement during its vibrations is [speed of sound =300 m/s^-1]

The equation of stationary wave along a stretched string given by y = 5 sin πx/3 cos 40πt, where x and y are in cm and t in second. The separation between two adjacent nodes is

In stationary waves, distance between a node and its nearest antinode is 20 cm . The phase difference between two particles having a separation of 60 cm will be

In a stationary wave represented by y = 2a cos(kx)sin(ωt) the intensity at a certain point is maximum when

A string fixed at both ends oscillates in 5 segments, length 10 m and velocity of wave is 20 ms^-1. What is the frequency?

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