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qUESTIONS

In a resonance pipe the first and second resonances are obtained at depths 22.7cm and 70.2 cm respectively. What will be the end correction (in cm)?

An open tube is in resonance with string. If tube is dipped in water so that 75% of length of tube is inside water, then the ratio of the frequency (v0) of tube to string now will be

An organ pipe open at one end is vibrating in first overtone and is in resonance with another pipe open at both ends and vibrating in third harmonic. The ratio of length of two pipe is

A closed organ pipe and an open organ pipe of same length produce 2 beats when they are set into vibrations simultaneously in their fundamental mode. The length of open organ pipe is now halved and of closed organ pipe is doubled, the number of beats produced will be

In open organ pipe, if fundamental frequency is v then the other frequencies are

An organ pipe, open from both end produces 5 beats per second when vibrated with a source of frequency 200 Hz. The second harmonic of the same pipes produces 10 beats per second with a source of frequency 420 Hz. The fundamental frequency of pipe is

A cylindrical tube, open at both ends, has a fundamental frequency f in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is

In the experiment for the determination of the speed of sound in air using the resonance column method, the length of the air column that resonates in the fundamental mode, with a tuning fork is 0.1m. When this length is changed to 0.35m the same tuning fork resonates with the first overtone. Calculate the end correction

A closed organ pipe and an open organ pipe are tuned to the same fundamental frequency. The ratio of their length is

A standing wave is represented by y = a sin (100t) cos (0.01x) , where Y and A are in millimetre, t is in seconds and x is in metre. The velocity of wave is

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